Tuesday, January 28, 2020
Applications Of Forced Convection Engineering Essay
Applications Of Forced Convection Engineering Essay    The experiment was carried out to verify the relationship between Nusselt number , Reynolds number and Prandtl Number using the different concepts of convection. Relative discussions and conclusions  were drawn including the various factors affecting the accuracy of the calculated results.  The main objective of this experiment was to verify the following heat transfer relationship:  Therefore, the experiment is conducted by an apparatus where hot ait from heater is generated and flow through copper tube. Different values of temperatures and pressure were taken and recorded in order to calculate. Besides, graphs plotted and analysed to have a better understanding of convection heat transfer.  Thus a Laboratory experiment was conducted where hot air from a heater was introduced through a copper tube with the help of a blower. Thermocouples were fixed in placed at various locations along the length of the copper tube. The different values of temperature and pressure were measured along with the various sections of the tube and other required values were recorded and calculated. Graphs were also plotted with the data obtained and then analysed.  INTRODUCTION  Heat transfer science deals with the time rate of energy transfer and the temperature distribution through the thermal system. It may be take place in three modes which is conduction, convection and radiation. Theory of convection is presented since this experiment is concerned about convective heat transfer. Convective is the mode of energy transfer between a solid surface and the adjacent liquid or gas that is in motion due to a temperature difference. It involves the combined effects of conduction and fluid motion.  There are two major type of convective  Forced convection is known as fluid motion generated by blowing air over the solid by using external devices such as fans and pumps.  The other type is natural convection which meant by a phenomenon that occurs in fluid segments and facilitated by the buoyancy effect. It is less efficient than forced convection, due to the absence of fluid motion. Hence, it depends entirely on the strength of the buoyancy effect and the fluid viscosity. Besides, there is no control on the rate of heat transfer.  Forced Convection  Force convection is a mechanism of heat transfer in which fluid motion is generated by an external source like a pump, fan, suction device, etc. Forced convection is often encountered by engineers designing or analyzing pipe flow, flow over a plate, heat exchanger and so on.  Convection heat transfer depends on fluids properties such as:  Dynamic viscosity (à µ)  Thermal conductivity (k)  Density (à à )  Specific heat (Cp)  Velocity (V)  Type of fluid flow (Laminar/Turbulent)  Newtons law of cooling  Where  h = Convection heat transfer (W/(m2.à °C)  A = Heat transfer area  = Temperature of solid surface (à °C)  = Temperature of the fluid (à °C)  The convective heat transfer coefficient (h) is dependent upon the physical properties of the fluid and the physical situation.  Applications of Forced Convection  In a heat transfer analysis, engineers get the velocity result by performing a fluid flow analysis. The heat transfer results specify temperature distribution for both the fluid and solid components in systems such as fan or heat exchanger. Other applications for forced convection include systems that operate at extremely high temperatures for functions for example transporting molten metal or liquefied plastic. Thus, engineers can determine what fluid flow velocity is necessary to produce the desired temperature distribution and prevent parts of the system from failing. Engineers performing heat transfer analysis can simply click an option to include fluid convection effects and specify the location of the fluid velocity results during setup to yield forced convection heat transfer results.  TYPICAL APPLICATIONS  Computer case cooling  Cooling/heating system design  Electric fan simulation  Fan- or water-cooled central processing unit (CPU) design  Heat exchanger simulation  Heat removal  Heat sensitivity studies  Heat sink simulation  Printed Circuit Board (PCB) simulation  Thermal optimization  Forced Convection through Pipe/Tubes  In a flow in tupe, the growth of the boundary layer is limited by the boundary of the tube. The velocity profile in the tube is characterized by a maximum value at the centerline and zero at the boundary.  For a condition where the tube surface temperature is constant, the heat transfer rate can be calculated from Newtons cooling law.  Reynolds Number  Reynolds number can be used to determine type of flow in fluid such as laminar or turbulent flow. Laminar flow occurs at low Reynolds numbers, where viscous forces are dominant. The condition of flow is smooth and constant fluid motion. Meanwhile, turbulent flow occurs at high Reynolds number and is dominated by inertial forces and it produce random eddies, vortices and other flow fluctuations.  Reynolds number is a dimensionless number. It is the ratio of the inertia forces to the viscous forces in the fluids. Equation for Reynolds Number in pipe or tube is as below:  Where  à à  = Fluid density (kg/m3)  V = Fluid velocity (m/s)  D = Diameter of pipe  ÃŽà ¼ = The dynamic viscosity of the fluid (Paà ·s or Nà ·s/mà ²)  ÃŽà ½ = Kinematic viscosity (ÃŽà ½ = ÃŽà ¼ / à à ) (mà ²/s)  Q = Volumetric flow rate (mà ³/s)  A = Pipe cross-sectional area (m2)  EXPERIMENT OVERVIEW  Apparatus  Figure 1 : Apparatus being used  The experimental apparatus comprises of a copper pipe, which is supplied with air by a centrifugal blower and heater as figure 1. The test section of the pipe is wound with a heating tape, which is covered with lagging. Six copper constantan thermocouples are brazed into the wall of the test section. Another six thermocouples extend into the pipe to measure the flowing air temperature. In addition five static pressure tapping are positioned in the tube wall. A BS 1042 standard orifice and differential manometer measure the air mass flow rate though the pipe.  Experimental Procedure  Fully close the valve which controlling the air flow rate.  Measure the everage intermal diameter (D) of the test section pipe by using a vernier calliper.  Adjust the inclination angle of the manometer bundle ÃŽà ± to 30à °.  Start the blower and turn the valve to the fully open position gradually,  Adjust the power input to the heating tape to its maximum valve and allow the apparatus to attain thermal equilibrium.  Take down the data and record  Pressure drop through the metering orifice  Pressure and temperature downstream of the orifice  Ammeter and voltmeter readings  Tube wall temperature along the testing section  Air temperature along the test section  Air pressure along the test section  Ambient temperature and pressure.  Repeat the foregoing procedure for another four different flow rate and adjust the heater input to give approximately the same wall temperature at each flow rate.  DATA AND MEASUREMENT TABLE  Property  Symbol  Units  Value  Barometric Pressure  Pb  mm Hg  741.60  Diameter of the test section pipe  Dp  m  0.038  Density of water (Manometers fluid)  à à   Kg/m3  1000  Angle of the manometers bundle  ÃŽà ±  degree  30  Property  Symbol  Units  Test  1  2  3  4  5  Pressure drop across orifice  ÃŽâ⬠H  mm H2O  685  565  460  360  260  Pressure drop d/s orifice to atmosphere  ÃŽâ⬠P  mm H2O  178  152  120  93  68  Air temperature downstream orifice  t  à °C  35  38  38  38  39  EMF (Voltage) across tape  V  Volts  230  200  165  142  129  Current through tape heater  I  Amps  7.3  6.3  5.5  5.0  4.0  Flowing air temperature  t1  à °C  35.0  36.9  38.2  40.0  41.4  Flowing air temperature  t2  à °C  36.1  37.7  38.9  40.6  41.9  Flowing air temperature  t3  à °C  43.1  43.6  43.4  44.4  45.6  Flowing air temperature  t4  à °C  42.2  42.4  42.4  43.5  44.6  Flowing air temperature  t5  à °C  49.6  48.6  47.0  47.3  48.1  Flowing air temperature  t6  à °C  63.2  59.6  55.7  54.3  54.6  Tube wall temperature  t7  à °C  38.9  40.0  40.6  41.9  43.0  Tube wall temperature  t8  à °C  81.20  73.6  65.9  62.2  61.2  Tube wall temperature  t9  à °C  99.8  89.1  77.5  71.5  69.5  Tube wall temperature  t10  à °C  105.9  93.9  81.3  74.6  72.4  Tube wall temperature  t11  à °C  106.5  94.5  81.8  75.1  73.1  Tube wall temperature  t12  à °C  108.1  95.5  82.3  75.0  72.5  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P1  mm H2O  385  324  255  195  145  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P2  mm H2O  264  223  175  132  99  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P3  mm H2O  210  181  141  108  79  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P4  mm H2O  108  97  81  57  42  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P5  mm H2O  23  31  20  16  14  Air static gauge pressure (ÃŽâ⬠l.sin ÃŽà ±)  P6  mm H2O  à ¢Ã¢â¬ °Ãâ 0  à ¢Ã¢â¬ °Ãâ 0  à ¢Ã¢â¬ °Ãâ 0  à ¢Ã¢â¬ °Ãâ 0  à ¢Ã¢â¬ °Ãâ 0  Sample Calculations  Based on 1st set data,  Power Input to the tape heater:  Power = = (230 x 7.3)/1000 = 1.679  Absolute Pressure downstream of the orifice:  741.60 + (178/13.6)=754.69 mmHg  Absolute Temperature downstream of the orifice:  T = t + 273 = 365+ 273 = 308 K  The Air Mass Flow Rate:  air =5.66x = = 231.88  231.88 Kg/hr = 0.06441 Kg/sec,  Since 1 Kg/hr = Kg/sec  Average Wall Temperature:  = (38.9+81.2+99.8+105.9+106.5+108.1)/6 =90.07  Average Air Temperature:  = (35+36.1+43.1+42.2+49.6+63.2)/6 = 44.87  The Bulk Mean Air (arithmetic average of mean air) Temperature:  = (35+63.2)/6 =49.1  The Absolute Bulk Mean Air (arithmetic average of mean air) Temperature:  49.1+273 =322.10 K  The Properties of Air at Tb:  Using the tables provided in Fundamentals of Thermal-Fluid Sciences by Yunus A.Cengel  From the table A-18 (Page958), Properties of Air at 1atm pressure at K  Density, à à  = 1.1029 kg/m3  Specific Heat Capacity, Cp = 1.006 kJ/(kg.K)  Thermal Conductivity, k = 0.0277 kW/(m.K)  Dynamic Viscosity, à µ = 1.95 x 10-5 kg/(m.s)  Prandtl Number, Pr = 0.7096  The Increase in Air Temperature:  63.2-35 = 28.2  The Heat Transfer to Air:  (231.88/3600) x 1.006 x 28.2 =1.827  Where: = Heat Transfer to air  = Mass flow rate  = Specific heat capacity  = Increase in air temperature  The Heat Losses:  1.679-1.827 = -0.148  Where: = Heat losses  = Heat Transfer to air  The Wall/Air Temperature Difference:  90.07-44.87 = 45.2  Where: = Wall/Air temperature difference  = Average air temperature  The Heat Transfer Coefficient:  = ((231.88/3600) x 1.006 x 28.2) / (3.14 x .0382 x 1.69 x 45.2) = 0.199 kW/ (m^2 .k)  Where:  = Mass flow rate  = Specific heat capacity  = Increase in air temperature  = Average Diameter of the Copper pipe.  = Length of the tube  = Wall/Air temperature difference  The Mean Air Velocity:  = (4 x (231.88/3600))/ (1.1029 x 3.14 x (0.0382 ^2) = 50.9575 m/s  Where:  = Mean air velocity  = Mass flow rate  = Density  = Average Diameter of the Copper pipe.  The Reynolds Number:  The Nusselt Number:  = Nusselt Number  = Average Diameter of the Copper pipe.  = Thermal conductivity  The Stanton Number:  Where:  St = Stanton Number  = Nusselt Number  = Prandtl number  Re = Reynolds number  The Pressure Drop across the testing section:  at Tb = 320.1 K  = Pressure drop across the testing section  = Absolute pressure downstream of orifice.  = Barometric Pressure  The Friction Factor:  RESULT  Power  Power  kW  1.679  1.260  0.908  0.710  0.516  Absolute Pressure downstream of the orifice  P  mm Hg  754.69  752.78  750.42  748.44  746.60  Absolute temperature downstream of the orifice  T  K  308  311  311  311  312  Pressure drop across the orifice  à ¢Ãâ Ã¢â¬  H  mm H20  685  565  460  360  260  Air mass flow Rate  air  231.88  209.31  188.57  166.60  141.18  Average wall Temperature  tw  90.07  81.1  71.57  66.72  65.28  Average air temperature  tair av  44.87  44.80  44.27  45.02  46.03  Bulk Mean air temperature  tb  49.1  48.25  46.95  47.15  48.0  Absolute bulk mean air temperature  Tb  K  322.1  321.25  319.95  320.15  321.0  Density at Tb  à à   1.1029  1.1058  1.1102  1.1095  1.1066  Specific Heat Capacity at Tb  Cp  1.0060  1.0060  1.0060  1.0060  1.0060  Thermal Conductivity at Tb  K  2.77  2.76  2.75  2.75  2.76  Dynamic Viscosity at Tb  ÃŽà ¼  1.95  1.95  1.94  1.94  1.95  Prandtl Number at Tb  Pr  0.7096  0.7096  0.7100  0.7100  0.7098  Increase in air temperature from t1 to t6  à ¢Ãâ Ã¢â¬  t a  28.2  22.7  17.5  14.3  13.2  Heat transfer to air  air  W  1.827  1.328  0.922  0.666  0.521  Heat losses  losses  W  -0.148  -0.068  -0.015  -0.044  -0.005  Wall/Air temperature difference  à ¢Ãâ Ã¢â¬  t m  45.2  36.3  27.3  21.7  19.25  Heat transfer Coefficient  h  0.199  0.180  0.167  0.151  0.133  Mean air velocity  Cm  50.9575  45.877  41.167  36.394  30.922  Reynoldss Number  Re  110096.353  99380.  144  89994.  330  79509.  225  67204.  418  Nusselt Number  Nu  274.4  249  232  209.8  184.1  Stanton Number  St  0.00351  0.00353  0.00363  0.0037  0.0039  Pressure Drop across the testing section  à ¢Ãâ Ã¢â¬  P  1746.42  1491.59  1176.73  912.57  667.08  Friction Factor  f  0.01378  0.0145  0.0141  0.0141  0.0143  Results  Plot A  Experiment  1  2  3  4  5  Y=ln(Nu x Pr-0.4)  5.75  5.65  5.58  5.48  5.35  X=ln(Re0.8)  9.29  9.21  9.13  9.03  8.89  Y-X  -3.54  -3.56  -3.55  -3.55  -3.54  Plot B  Experiment  1  2  3  4  5  Y=Nu  274.4  249  232  209.8  184.1  X=Re x Pr  78124.37  70520.15  63895.97  56451.55  47701.69  Stanton number:  Reynolds Analogy:  Experiment  1  2  3  4  5  Friction factor  0.01378  0.0145  0.0141  0.014  0.0143  Reynolds Analogy  0.00689  0.00725  0.00705  0.007  0.00715  Stanton number  0.00351  0.00353  0.00363  0.0372  0.0386  DISCUSSION  In order to get more accurate results, there are some suggestions like cleaning the manometer, checking the insulation on the pipe and making sure the valve is closed tightly.  An additional way to prove the heat transfer equation is by re-arranging it.  Nu = 0.023 x (Re0.8 x Pr 0.4)  Substituting in the experimental values into the above equation from section 5.0 returns the following results below:  Experiment  1  2  3  4  5  Y=Nu  274.4  249  232  209.8  184.1  X=Re0.8 x Pr0.4  9415.08  8674.51  8014.48  7258.34  6344.14  Y/X  0.029  0.0287  0.0289  0.0289  0.029  Comparing this to the heat transfer constant, it shows that there is a little difference only which can be negligible.  It can also be done by taking the gradient of the line from the plot Nu against (Re0.8 x Pr0.4)  as shown below:  CONCLUSION  A better understanding of the heat transfer was achieved through conducting the experiment. Theoretical sums and experimental values were found to be approximately similar and the different sources of error have been identified.  The main objective of this experiment was to verify the following heat transfer relationship:  Nu = 0.023 x (Re0.8 x Pr 0.4)  Therefore, relation of forced convective heat transfer in pipe is cleared and the objectives were completed.    
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